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# The coagulation of 200 mL of a positive colloid took place . When 0.73 g Hcl was added to it without changing the volume much . The flocculation value of Hcl for the colloid is

$(a)\;0.365\qquad(b)\;36.5\qquad(c)\;100\qquad(d)\;150$

Can you answer this question?

Explanation :
200 mL of the sol needs = $\;\large\frac{0.73 g}{36.5 g/mol}=0.02\;mol\;$
$=20\;m\;mol$
1000 mL of the sol will require = $\;\large\frac{20 \times 1000}{200}=100m\;mol\;$
Therefore , value of Hcl for the colloid is 100 .
answered Mar 18, 2014 by