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The coagulation of 200 mL of a positive colloid took place . When 0.73 g Hcl was added to it without changing the volume much . The flocculation value of Hcl for the colloid is


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Answer : 100
Explanation :
200 mL of the sol needs = $\;\large\frac{0.73 g}{36.5 g/mol}=0.02\;mol\;$
1000 mL of the sol will require = $\;\large\frac{20 \times 1000}{200}=100m\;mol\;$
Therefore , value of Hcl for the colloid is 100 .
answered Mar 18, 2014 by yamini.v

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