Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The number of moles of lead nitrate needed to coagulate a mol of colloidal $\;[AgI]I^{-}\;$ is


Can you answer this question?

1 Answer

0 votes
Answer : 1
Explanation :
$2 [AgI]I^{-} + Pb^{2+} \to PbI_{2} + 2AgI$
Thus 2 moles of $[AgI]I^{-}\;$ are coagulated by 1 mole of $\;Pb^{2+}\;$ i.e ; 1 mole of $\;Pb(NO_{3})_{2}$
answered Mar 18, 2014 by yamini.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App