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Which of the following reactions shows the formation of positively / negatively charged sol correctly?

(a) $FeCl_3 + H_2O(excess) \longrightarrow Fe_2O_3.xH_2O | H^+$
(b) $FeCl_3 + H_2O(excess) \longrightarrow Fe_2O_3.xH_2O | Fe^{3+}$
(c) $FeCl_3 + NaOH(aq) \longrightarrow Fe_2O_3.xH_2O | Fe^{3+}$
(d) $FeCl_3 + NaOH(aq) \longrightarrow Fe_2O_3.xH_2O | OH^+$
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Answer: $FeCl_3 + H_2O(excess) \longrightarrow Fe_2O_3.xH_2O | Fe^{3+}$
If ferric chloride is added to excess of hot water, a positively chrged sol of hydrated ferric hydroxide is formed.
$FeCl_3 + H_2O(excess) \longrightarrow Fe_2O_3.xH_2O | Fe^{3+}$
If $FeCL_3$ is added to NaOH solution, a negatively charged sol is obtained.
$FeCl_3 + NaOH(aq) \longrightarrow Fe_2O_3.xH_2O | OH^-$
answered Mar 18, 2014 by mosymeow_1
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