$(a)\;\large\frac{1}{n}\qquad(b)\;log\;k\qquad(c)\;-log\;k\qquad(d)\;n$

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Answer : $\;\large\frac{1}{n}$

Explanation :

For the adsorption of a gas on a solid $\;\large\frac{x}{m}=kp^{\large\frac{1}{n}}\;$

Therefore , $\;log \large\frac{x}{m}=log\;k+\large\frac{1}{n}\;log\;p\;$ (ontaking log can both sides )

Therefore , plot of $\;\large\frac{x}{m}\;$ vs $\;log\;p\;$ will be linear with slope = $\;\large\frac{1}{n}$

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