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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Thermodynamics
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Consider the reaction $N_2 + 3H_2 \rightarrow 2NH_3$ carried out at constant temperature and pressure. If $ \Delta H\: and\: \Delta U$ are the enthalpy and internal energy changes for the reaction, which of the following expressions is true?

$\begin {array} {1 1} (A)\;\Delta H > \Delta U & \quad (B)\;\Delta H < \Delta U \\ (C)\;\Delta H = \Delta U & \quad (D)\;\Delta = 0 \end {array}$

Can you answer this question?

1 Answer

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$ \Delta H = \Delta U = \Delta n_gRT$
$ \Delta n_g $ = mole of (gaseous products – gaseous reactants) = -ve
Thus, $ \Delta H < \Delta U$
Ans : (B)
answered Mar 18, 2014 by thanvigandhi_1

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