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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Thermodynamics
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A reaction is non-spontaneous at the freezing point of water but is spontaneous at the boiling point of water, then

  $ \Delta H$ $ \Delta S$
A + Ve + Ve
B - Ve - Ve
C - Ve + Ve
D + Ve - Ve

 

Can you answer this question?
 
 

1 Answer

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For spontaneity; $ \Delta G = -ve$
$ \Delta G = \Delta H - T\Delta S$
$\Delta H$, for endothermic process is +ve
At lower temperature, $ \Delta S$ +ve hence $ \Delta G$ = +ve. But at high temperature, $ T \Delta S$ will be greater than
$ \Delta H$, hence $ \Delta G$ = -ve, spontaneous.
Ans : (A)
answered Mar 18, 2014 by thanvigandhi_1
 

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