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The compound formed as a result of oxidation of ethyl benzene by $KMnO_4$ is

$\begin{array}{1 1}(a)\;\text{Benzyl alcohol}\\(b)\; \text{Benzophenone}\\(c)\;\text{Acetophenone}\\(d)\;\text{Benzoic acid}\end{array}$

1 Answer

When oxidises with alkaline $KMnO_4$ or acidic $Na_2Cr_2O_7$,the entire side chain (in benzene homologues) with atleast one H at $\alpha$-carbon,regardless of length is oxidised to -COOH.
Hence (d) is the correct answer.
answered Mar 19, 2014 by sreemathi.v