$(a)\;1\;g\qquad(b)\;2\;g\qquad(c)\;3\;g\qquad(d)\;5\;g$

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Answer : $\;1\;g$

Explanation :

According to freundlich equation , $\;\large\frac{x}{m}=KP^{\large\frac{1}{n}}\;$

or $\;log \large\frac{x}{m}=log K + \large\frac{1}{n} log P$

Therefore , plot of $\;log \large\frac{x}{m}\;$ vs log P is a straight line with slope = $\;\large\frac{1}{n}\;$ and intercept = log K

Thus , $\;\large\frac{1}{n}=tan \theta = tan 45^{0}=1\;or\;n=1$

At $\;P=0.5 atm\; $ and K=10

$\large\frac{x}{m}=10 (0.5)=5$

When m=1 g

Therefore , x (i . e , amount adsorbed per gram ) = 5 g

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