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Adsorption is generally an

$(a)\;exothermic\;process\qquad(b)\;endothermic\;process\qquad(c)\;may\;be\;exothermic\;or\;endothrermic\qquad(d)\;neither\;exothrmic\;nor\;endothermic$

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Answer : exothermic process
Explanation :
Adsorption is generally accompanied by decrease in randamness i.e , $\;\bigtriangleup S\;$ for the process is - ve . As
$+ \bigtriangleup G = \bigtriangleup H - T \bigtriangleup S $
$(-ve) = \bigtriangleup H - (+ve) (-ve)$
$ \bigtriangleup H = (-ve)$
Therefore , for adsorption , $\; \bigtriangleup H\;$ is generally -ve i.e , process is generally exothermic .
answered Mar 19, 2014 by yamini.v
 

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