Browse Questions

# In the stoichiometry of natural faujasite -a zeolite with formula $\;Na_{x}[(Alo_{2})_{56}(Sio_{2})_{136}].2SOH_{2}O\;$ the value of x is

$(a)\;56\qquad(b)\;136\qquad(c)\;250\qquad(d)\;None\;of\;these$

Explanation :
Here , $\;SiO_{2}\;$ and $\;H_{2}O\;$ do net carry any charge . The charge present in $\;AlO_{2}\;$ unit is -1 (+3 on Al and -4 on two O - atoms) . Thus negative charge present on 56 $\;AlO_{2}\;$ units is -56 . Therefore , $\;56 Na^{+}\;$ ions are present in one molecule of faujasite