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Which one of the following has the minimum boiling point?

$\begin{array}{1 1}(a)\;\text{n-butane}\\(b)\; \text{1-butyne}\\(c)\;\text{1-butene}\\(d)\;\text{Isobutene}\end{array}$

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1 Answer

Among the isomeric alkanes,the normal isomer has a higher boiling point than the branched chain isomer.The greater the branching of the chain,the lower is the boiling point.
The n-alkanes have larger surface area in comparision to branched chain isomer (as the shape approaches that of a sphere in the branched chain isomers).Thus,intermolecular forces are weaker in branched chain isomers.Therefore,they have lower boiling points in comparision to straight chain isomers.
Hence (b) 1-butyne is the correct option.
answered Mar 19, 2014 by sreemathi.v