$(a)\;44\qquad(b)\;46\qquad(c)\;43\qquad(d)\;4$

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Answer : $46$

Explanation :

A minimum of 4.6 mL of AB is required to coagulate the sol . The moles of AB in the sol is

$=\large\frac{4.6 \times 0.1}{10}=0.046\;moles$

This means that a minimum of 0.046 moles or $\;0.046 \times 1000 = 46\;$milli moles are required for coagulating 1 litre of sol .

Therefore , Flocculation value of AB for $\;As_{2}S_{3}\;$ sol = 46 .

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