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When Grignard reagent is treated with water,alcohol,ammonia,$1^o$ amine,$2^o$ amine,alkyne-1 or carboxylic acid.We get alkane corresponding to alkyl part of Grignard reagent.In Grignard reagent C-atom is more electronegative than magnesium,hence its alkyl part acts are nucleophile and thus it will take an active hydrogen atom(H-atom that undergoes acylation) or acidic hydrogen atom to give its corresponding alkane.Also it is known that stronger acid displaces weak acid from weak acid salt.Molecular formula of an alcohol,0.44g of which when treated with $CH_3MgI$ liberates 112ml of $CH_4$ is

$\begin{array}{1 1}(a)\;C_5H_9OH&(b)\;C_4H_9OH\\(c)\;C_6H_{13}OH&(d)\;C_5H_{11}OH\end{array}$

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A)
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Number of moles of alcohol=number of moles of $CH_4$
$\large\frac{0.44}{MM}=\frac{112}{22400}$
$\therefore MM=88$
$n=\large\frac{88-18}{14}$$=5$
$\therefore$ Molecular formula of alcohol $=C_5H_{11}OH$
Hence (d) is the correct answer.
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