logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Hydrocarbons
0 votes

When Grignard reagent is treated with water,alcohol,ammonia,$1^o$ amine,$2^o$ amine,alkyne-1 or carboxylic acid.We get alkane corresponding to alkyl part of Grignard reagent.In Grignard reagent C-atom is more electronegative than magnesium,hence its alkyl part acts are nucleophile and thus it will take an active hydrogen atom(H-atom that undergoes acylation) or acidic hydrogen atom to give its corresponding alkane.Also it is known that stronger acid displaces weak acid from weak acid salt.Molecular formula of an alcohol,0.44g of which when treated with $CH_3MgI$ liberates 112ml of $CH_4$ is

$\begin{array}{1 1}(a)\;C_5H_9OH&(b)\;C_4H_9OH\\(c)\;C_6H_{13}OH&(d)\;C_5H_{11}OH\end{array}$
Can you answer this question?
 
 

1 Answer

0 votes
Number of moles of alcohol=number of moles of $CH_4$
$\large\frac{0.44}{MM}=\frac{112}{22400}$
$\therefore MM=88$
$n=\large\frac{88-18}{14}$$=5$
$\therefore$ Molecular formula of alcohol $=C_5H_{11}OH$
Hence (d) is the correct answer.
answered Mar 19, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...