logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The coagulation of 100 ml of a colloidal solution of gold is completely prevented by the addition of 0.25 g of starch to it before adding 1 ml of 10% Nacl solution . Calculate the gold number of starch .

$(a)\;20\qquad(b)\;0.25\qquad(c)\;2.5\qquad(d)\;25$

Can you answer this question?
 
 

1 Answer

0 votes
Answer : 25
Explanation :
Amount of starch added to 100 mL of gold sol required to prevent coagulation of 1 mL of $\;10\%\;$ Nacl solution = 0.25 g = 250 mg
Starch required to be added to 10 mL to gold sol to completely . Prevent coagulation by 1 mL of $\;10\%\;$ Nacl solution .
$=\large\frac{250}{100}\times 10 = 25 mg$
Therefore , Gold number of starch = 25
answered Mar 19, 2014 by yamini.v
what is the actual formula for this problem
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...