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The output current versus time graph of a Diode as a rectifier The average value of output current is :

$(a)\;O \\(b)\;\large\frac{I_0}{2}\\(c)\;\large\frac{2I_0}{\pi} \\(d)\;I_0 $
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The average value of output is $=\int \limits_0^{T/2} I.dt$
$I= I_0\;\sin wt$
$\qquad= \large\frac{2I_0}{\pi}$
Hence c is the correct answer.
answered Mar 19, 2014 by meena.p
 

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