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Cleavage of ozonide gives aldehyde and ketone if it is carried out using

$\begin{array}{1 1}(a)\;Zn/H_2O&(b)\;H_2O\\(c)\;Zn/H_2O,DMS&(d)\;\text{All of these}\end{array}$
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$Zn-H_2O$ cleavage gives ZnO.$(CH_3)_2S$(DMS) cleavage gives $(CH_3)_2S=O$(DMSO).But $H_2O$ cleavage gives weak oxidising agent $H_2O_2$
Hence (c) is the correct answer.
answered Mar 19, 2014 by sreemathi.v

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