Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Thermodynamics
Answer
Comment
Share
Q)

If the values of $ \Delta H_f^{\circ}\: for\: CH_4(g), C_2H_6(g), CO_2(g)\: and \: H_2O(l)$ are respectively $-74.85, -84.68, -393.5 \: and\: -286\: kJ/mol,$ predict which is more efficient fuel?

$\begin {array} {1 1} (A)\;ethane & \quad (B)\;methane \\ (C)\;Both \: are\: equally\: efficient & \quad (D)\;Can’t\: be\: determined \end {array}$

1 Answer

Comment
A)
$CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l)$
$ \Delta H_1 = [2(-286) + (-393.5)] – [-74.84]$
$ = -890.66\: kJ/mol$
$C_2H_6(g) + \large\frac{7}{2}$$ O_2(g) \rightarrow 2CO_2(g) + 3H_2O(l)$
$ \Delta H_2 = [3 \Delta H_f(H_2O) + 2 \Delta H_f(CO_2)] – [ \Delta H_f(C_2H_6) + \large\frac{7}{2} \times 0]$
$ = [3(-286) + 2(-393.5) – [-84.68]$
$ = -1560.32\: kJ$
Now, heat evolved per gram of $CH_4, H_1 = \large\frac{890.66}{16}$$ = 55.66\: kJ/g$
Heat evolved per gram of $ C_2H_6, H_2 = \large\frac{1560.32}{30}$$ = 52.01\: kJ/g$
Since, $ H_1 > H_2$ Thus, methane is more efficient fuel.
Ans : (B)
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...