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Addition of HCl to 2-methyl-2-butene mainly gives

$\begin{array}{1 1}(a)\;\text{1-chloro-2-methylbutane}\\(b)\;\text{2-chloro-2-methylbutane}\\(c)\;\text{2-chlorobutane}\\(d)\;\text{1-chlorobutane}\end{array}$

1 Answer

According to Markownikoff's rule,the negative part of the unsymmetrical reagent adds to less hydrogenated carbon atom of the double bond.
Hence (b) is the correct answer.
answered Mar 20, 2014 by sreemathi.v