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# Addition of HCl to 2-methyl-2-butene mainly gives

$\begin{array}{1 1}(a)\;\text{1-chloro-2-methylbutane}\\(b)\;\text{2-chloro-2-methylbutane}\\(c)\;\text{2-chlorobutane}\\(d)\;\text{1-chlorobutane}\end{array}$

According to Markownikoff's rule,the negative part of the unsymmetrical reagent adds to less hydrogenated carbon atom of the double bond.
Hence (b) is the correct answer.