# The general solution of $\large\frac{dy}{dx}$$=2xe^{x^2-y} is: $(A)\;e^{x^2-y}=c \quad (B)\;e^{-y}+e^{x^2}=c \quad(C)\;e^y=e^{x^2}+c \quad (D)\;e^{x^2}+y=c$ ## 1 Answer Toolbox: • Linear equation of the type \large\frac{dy}{dx}$$=f(x)$ can be solved by seperating the variable, and then integrating
• $\int e^x dx=e^x+c$