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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Thermodynamics
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The change in internal energy of a gas $\;du=$

$(a)\;\large\frac{nR}{r-1}\;dT\qquad(b)\;nC_{v}dT\qquad(c)\;\large\frac{nC_{p}}{r} dT\qquad(d)\;All\;the\;above$

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1 Answer

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Answer : $\;All\;the\;above$
Explanation :
$du=nC_{v}dT$
$\large\frac{C_{p}}{C_{v}}=r$
$C_{v}=\large\frac{k}{r-1}$
answered Mar 20, 2014 by yamini.v
 

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