Browse Questions

# General solution of $\frac{dy}{dx} + y\tan x = \sec x$ is

$(A)\;y\sec x=\tan x+c \quad (B)\;y\tan x=\sec x+c\quad(C)\;\tan x=y\tan x+c \quad(D)\;x\sec x=\tan y+c$

Toolbox:
• A linear differential equation of the form $\large\frac{dy}{dx}$$+Py=Q has general solution as ye^{\int pdx}=\int Qe^{\int pdx}dx+c Given \large\frac{dy}{dx}$$+y\tan x=\sec x$