Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Let $S$ be a non empty subset of $R$. Consider the following statement: $P$: There is a rational number $x \in S$ such that $x\gt 0$. Then, which of the following statements is the negation of statement $P$:

$\begin{array}{1 1}(A) x \in \; and x \leq 0 \Rightarrow \text{x is not rational} \\ (B) \text{Every rational number} x \in \; satisfies\; x \leq 0 \\(C) \text{There is no rational number} x \in such that x \leq 0 \\(D) \text{There is a rational number} x \in such\; that \;x \leq 0 \end{array}$

Can you answer this question?

1 Answer

0 votes
The given statement is $P$: There is a rational number $x \in S$ such that $x\gt 0$.
The negation would be: There is no rational number $x \in S$ such that $x \gt 0$ which is equivalent to all rational numbers $x \in S$ satisfy $x \leq 0$
answered Mar 20, 2014 by balaji.thirumalai

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App