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Home  >>  CBSE XII  >>  Math  >>  Differential Equations
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The degree of the differential equation $\sqrt{1+\bigg(\large\frac{dy}{dx}\bigg)^2}$$=x$ is ___________.

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  • If a differential equation cannot be expressed as a polynomial in differential coefficients, then its degree is not defined.
The degree of the differential equation
$\sqrt{1+\bigg(\large\frac{dy}{dx}\bigg)^2}$$=x$ is not defined
This can be written as
$\bigg[1+\bigg(\large\frac{dy}{dx}\bigg)^2\bigg]^{\large\frac{1}{2}}$$=x$ is not defined
Clearly this differential equation cannot be expressed as a polynomial in differential coefficients.
So the degree is not defined
answered May 22, 2013 by meena.p
 
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