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Differential Equations
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The degree of the differential equation $\sqrt{1+\bigg(\large\frac{dy}{dx}\bigg)^2}$$=x$ is ___________.
cbse
class12
ch9
sec-a
q76ii
p201
fitb
exemplar
easy
math
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asked
Jan 20, 2013
by
sreemathi.v
edited
May 22, 2013
by
meena.p
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1 Answer
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If a differential equation cannot be expressed as a polynomial in differential coefficients, then its degree is not defined.
The degree of the differential equation
$\sqrt{1+\bigg(\large\frac{dy}{dx}\bigg)^2}$$=x$ is not defined
This can be written as
$\bigg[1+\bigg(\large\frac{dy}{dx}\bigg)^2\bigg]^{\large\frac{1}{2}}$$=x$ is not defined
Clearly this differential equation cannot be expressed as a polynomial in differential coefficients.
So the degree is not defined
answered
May 22, 2013
by
meena.p
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