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Home  >>  CBSE XII  >>  Math  >>  Model Papers
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Evaluate $\int\large\frac{dx}{sin^2x\:cos^2x}$

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$\int\large\frac{dx}{sin^2x\:cos^2x}$
Multiplying and dividing by 4
=4 $\int\large\frac{dx}{4sin^2x\:cos^2x}$$=4\int \large\frac{dx}{sin^22x}$
$=4\int cosec^22x\:dx=4.\large\frac{-cot 2x}{2}$
$=-2cot 2x+c$
answered Mar 20, 2014 by rvidyagovindarajan_1
 
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