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# Select the major product formed from the treatment of 2-bromobutane and alcoholic KOH

$\begin{array}{1 1}(a)\;CH_2=CHCH_2CH_3&(b)\;Cis-CH_3CH=CHCH_3\\(c)\;trans.CH_3CH=CHCH_3&(d)\;CH_2=CHCH_3\end{array}$

$E2$ reactions are selectively trans
Hence (c) trans.$CH_3CH=CHCH_3$ is the correct answer.