Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Hydrocarbons
0 votes

Select the major product formed from the treatment of 2-bromobutane and alcoholic KOH

$\begin{array}{1 1}(a)\;CH_2=CHCH_2CH_3&(b)\;Cis-CH_3CH=CHCH_3\\(c)\;trans.CH_3CH=CHCH_3&(d)\;CH_2=CHCH_3\end{array}$

Can you answer this question?

1 Answer

0 votes
$E2$ reactions are selectively trans
Hence (c) trans.$CH_3CH=CHCH_3$ is the correct answer.
answered Mar 20, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App