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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Hydrocarbons
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Select the major product formed from the treatment of 2-bromobutane and alcoholic KOH

$\begin{array}{1 1}(a)\;CH_2=CHCH_2CH_3&(b)\;Cis-CH_3CH=CHCH_3\\(c)\;trans.CH_3CH=CHCH_3&(d)\;CH_2=CHCH_3\end{array}$

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$E2$ reactions are selectively trans
Hence (c) trans.$CH_3CH=CHCH_3$ is the correct answer.
answered Mar 20, 2014 by sreemathi.v
 

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