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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Thermodynamics

S1: $ \Delta G$ and $ \Delta H$ of a reaction always have the same sign. \[\] S2: $ \Delta G_f^{\circ}$ of carbon(graphite) is equal to zero.

$\begin {array} {1 1} (A)\;\text{If both S1 & S2 are correct and S2 is correct explanation of S1.} \\ (B)\;\text{If both S2 & S1 are correct but S2 is not correct explanation of S1.} \\ (C)\;\text{If S1 is correct but S2 is wrong.} \\ (D)\; \text{If S1 is wrong but S2 is correct.} \end {array}$

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1 Answer

$ \Delta G = \Delta H – T \Delta S$. So. if $\Delta H < T\Delta S, \Delta G > 0,$ then $ \Delta H < 0$, i.e, both will have different signs.
Ans : (D)
answered Mar 20, 2014 by thanvigandhi_1
 

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