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When the same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide evolved is

$(a)\;1:1 \\ (b)\;1:3\\(c)\;2:1 \\(d)\;9:4 $

1 Answer

(i) Reaction of zinc and $H_2SO_4$ (excess)
$Zn +H_2sO_4 \longrightarrow ZnSO_4+H_2$
(ii) Reaction of zinc and $NaOH$ (excess)
$Zn+2NaOH \longrightarrow Na_2ZnO_2+H_2$
Ratio of volumes of hydrogen evolved $=\large\frac{1}{1}$$=1:1$
Hence a is the correct answer.
answered Mar 21, 2014 by meena.p
 

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