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When propyne is treated with aqueous $H_2SO_4$ in presence of $HgCO_4$,the major product is

$\begin{array}{1 1}(a)\;\text{Propanal}\\(b)\;\text{n-propyl hydrogen sulphate}\\(c)\;\text{Acetone}\\(d)\;\text{Propanol}\end{array}$

$CH_3C\equiv CH+H_2O\quad\underrightarrow{H_2SO_4}\quad \big[CH_3C(OH)=CH_2\big]\quad\underrightarrow{\text{tautomerisation}}\quad CH_3COCH_3$
Hence (c) Acetone is the correct answer.