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Reaction of HBr with propene in the presence of peroxide gives

$\begin{array}{1 1}(a)\;\text{Isoprophyl bromide}\\(b)\;\text{3-bromopropane}\\(c)\;\text{Allyl bromide}\\(d)\;\text{n-propyl bromide}\end{array}$

1 Answer

$CH_3-CH=CH_2\quad\underrightarrow{HBr/H_2O_2}\quad CH_3-CH_2-CH_2Br$
In presence of peroxide,addition of HBr takes place according to Anti-Markownikoff's rule.
Hence (d) n-propyl bromide is the correct option.
answered Mar 21, 2014 by sreemathi.v