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Q)

Chlorination of an alkane involves the attack of

$\begin{array}{1 1}(a)\;\text{An electrophile}&(b)\;\text{A nucleophile}\\(c)\;\text{A base}&(d)\;\text{A free radical}\end{array}$

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A)
In presence of sunlight the $Cl_2$ molecules break to furnish free radical.
Under the influence of high temperature (heat) or uv light, alkanes will react with chlorine or bromine via a free radical substitution reaction mechanism.
The basic reaction is: $R_3C-H + Cl_2 \large\xrightarrow{[heat/uv]} R_3C-Cl + HCl$
Hence (d) A free radical is the correct option.
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