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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Hydrocarbons
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Chlorination of an alkane involves the attack of

$\begin{array}{1 1}(a)\;\text{An electrophile}&(b)\;\text{A nucleophile}\\(c)\;\text{A base}&(d)\;\text{A free radical}\end{array}$

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In presence of sunlight the $Cl_2$ molecules break to furnish free radical.
Hence (d) A free radical is the correct option.
answered Mar 21, 2014 by sreemathi.v

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