logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Hydrocarbons
0 votes

Chlorination of an alkane involves the attack of

$\begin{array}{1 1}(a)\;\text{An electrophile}&(b)\;\text{A nucleophile}\\(c)\;\text{A base}&(d)\;\text{A free radical}\end{array}$

Can you answer this question?
 
 

1 Answer

0 votes
In presence of sunlight the $Cl_2$ molecules break to furnish free radical.
Hence (d) A free radical is the correct option.
answered Mar 21, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...