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# Which has the maximum number of atoms?

$(a)\;\text{24 g of C(12)} \\ (b)\;\text{56 g of Fe(56)} \\(c)\; \text{27 g of Al(27)} \\(d)\;\text{108 g of Ag(108) }$

Number of atoms
$24 \;g$ of carbon $=2 \times 6.023 \times 10^{23}$
$56 \;g$ of iron $=1 \times 6.023 \times 10^{23}$
$27 \;g$ of aluminium $=1 \times 6.023 \times 10^{23}$
$108 \;g$ of silver $=1 \times 6.023 \times 10^{23}$
Hence the maximum number of atoms is in 24 g of carbon (ie 2 moles of carbon)
Hence a is the correct answer.