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# What is X in the following sequence of reactions?$X\quad\underrightarrow{Na}\quad Y\quad\underrightarrow{NaOH/CaO}\quad CH_4$

$\begin{array}{1 1}(a)\;\text{Methanoic acid}\\ (b)\;\text{Ethanoic acid}\\(c)\;\text{Propane}\\(d)\;\text{Methane}\end{array}$

$CH_3COOH\quad\underrightarrow{Na}\quad CH_3COONa\quad\underrightarrow{NaOH,CaO}\quad CH_4+Na_2CO_3$
Hence (b) Ethanoic acid is the correct answer.