$(a)\;< 1\qquad(b)\; > 1\qquad(c)\;=1\qquad(d)\;zero$

Answer : $\;< 1$

Explanation :

Path 1 : $\;dQ_{1}=du_{1}+dv$

$\bigtriangleup Q_{1} =\bigtriangleup u_{1} + \bigtriangleup w_{1}$

Path 2 : $\;\bigtriangleup Q_{2}=\bigtriangleup u_{2}+\bigtriangleup w_{2}$

Since for both the paths , the initial and final states are the same , $\;\bigtriangleup u\;$ is the same

$\bigtriangleup Q_{2} > \bigtriangleup Q_{1}$

$nC_{2} \bigtriangleup T > n C_{1} \bigtriangleup T$

$\large\frac{C_{1}}{C_{2}} < 1$

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