Browse Questions
Thermodynamics

# P - T graph of an ideal gas is shown . Density of the gas at A is ' d ' and then density of the gas at B is

$(a)\;\large\frac{3d}{2}\qquad(b)\;\large\frac{2d}{3}\qquad(c)\;\large\frac{5d}{3}\qquad(d)\;\large\frac{3d}{5}$

Answer : $\;\large\frac{3d}{2}$
Explanation :
$PV=nRT \quad$ n=no.of moles = mass / molar mass
Therefore , $\;P=\large\frac{mRT}{VM}=\large\frac{\rho RT}{M}$
$\rho = \large\frac{MP}{RT}$
$d_{A}=\large\frac{M}{R}\;\large\frac{P_{0}}{T_{0}}$
$d_{B}=\large\frac{M}{R}\;\large\frac{3P_{0}}{2T_{0}}$
$d_{B}=\large\frac{3}{2}\;d_{A}$