logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Thermodynamics
0 votes

P - T graph of an ideal gas is shown . Density of the gas at A is ' d ' and then density of the gas at B is

$(a)\;\large\frac{3d}{2}\qquad(b)\;\large\frac{2d}{3}\qquad(c)\;\large\frac{5d}{3}\qquad(d)\;\large\frac{3d}{5}$

Can you answer this question?
 
 

1 Answer

0 votes
Answer : $\;\large\frac{3d}{2}$
Explanation :
$PV=nRT \quad $ n=no.of moles = mass / molar mass
Therefore , $\;P=\large\frac{mRT}{VM}=\large\frac{\rho RT}{M}$
$\rho = \large\frac{MP}{RT}$
$d_{A}=\large\frac{M}{R}\;\large\frac{P_{0}}{T_{0}}$
$d_{B}=\large\frac{M}{R}\;\large\frac{3P_{0}}{2T_{0}}$
$d_{B}=\large\frac{3}{2}\;d_{A}$
answered Mar 21, 2014 by yamini.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...