Browse Questions

# $B\quad\underrightarrow{\text{Lindlar catalyst}/H_2}\quad R-C\equiv C-R\quad\underrightarrow{Na/NH_3}\quad A.$ A and B are geometrical isomers $(R-CH=CH-R)$

$\begin{array}{1 1}(a)\;\text{A is cis,B is trans}\\(b)\;\text{A is trans,B is cis}\\(c)\;\text{A & B both are cis}\\(d)\;\text{A & B both are trans}\end{array}$

Cis products is obtained when we use Lindlar's catalyst and trans product is obtained when we use $Na/liq.NH_3$ (or) $LiAlH_4$
Hence (b) is the correct option.