# Benzyl chloride $(C_6H_5CH_2Cl)$ can be prepared from toluene by chlorination with

$\begin{array}{1 1}(a)\;SO_2Cl_2&(b)\;SOCl_2\\(c)\;Cl_2&(d)\;NaOCl\end{array}$

Chlorination of toluene to form benzyl chloride is a free radical substitution reaction.Only $Cl_2$ can give $Cl$(chlorine free radical) in presence of light.
Hence (c) is the correct option.