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The number of neutrons in dipositive zinc ion with mass number 70 is

$(a)\;34 \\ (b)\;36 \\(c)\;38 \\(d)\;40 $
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Neutrons in $zn^{2+}$
Atomic weight $=70$
Atomic number $=30$
Number of neutrons $=40$
Hence d is the correct answer.
answered Mar 21, 2014 by meena.p

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