$(CH_3)_3CMgCl$ on reaction with $D_2O$ produces

$\begin{array}{1 1}(a)\;(CH_3)_3CD&(b)\;(CH_3)_3OD\\(c)\;(CD_3)_3CD&(d)\;(CD_3)_3OD\end{array}$

hence (a) is the correct answer.
answered Mar 21, 2014