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Propyne and propene can be distinguished by

$\begin{array}{1 1}(a)\;\text{Concentrated }H_2SO_4&(b)\;Br_2\;in\;CCl_4\\(c)\;\text{dilute }KMnO_4&(d)\;AgNO_3\text{ in ammonia}\end{array}$

1 Answer

The terminal hydrogen is acidic in $CH_3C\equiv CH$(propyne and it reacts with ammonical $AgNO_3$.In propene,$CH_3CH=CH_2$ there is no acidic hydrogen.
Hence (d) is the correct option.
answered Mar 21, 2014 by sreemathi.v