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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Thermodynamics

The work done in process ABC (in atm litre)

$(a)\;\pi\qquad(b)\;\large\frac{\pi}{4}\qquad(c)\;\large\frac{\pi}{2}\qquad(d)\;2 \pi$

1 Answer

Answer : $\;\large\frac{\pi}{2}$
Explanation :
Work done = $\;\large\frac{1}{2}\;$ Area of ellipse
$= \large\frac{1}{2}\; \pi$ [semi major Axis $\;\times\;$ semi minor Axis]
$= \large\frac{1}{2} \pi \times (2-1) \times (\large\frac{3-1}{2})$
$=\large\frac{\pi}{2}\;.$
answered Mar 21, 2014 by yamini.v
 

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