$\begin{array}{1 1}(a)\;CuCl\\ (b)\;Cu_2Cl \\(c)\;CuCl_2& \\(d)\;\text{None of these}\end{array} $

Eq.mass of copper chloride =99(given)

Eq.mass of chlorine=35.5(given)

$\therefore$ Eq.mass of copper chloride =Eq.mass of copper + Eq.mass of chlorine

$\therefore$ 99=E of Cu +35.5

$\therefore$ E of Cu=99-35.5=63.5

$\therefore$ Valency of copper =$\large\frac{\text{At.mass of copper}}{\text{Eq.mass of copper}}$

$\Rightarrow \large\frac{63.5}{63.5}$$=1$

$\therefore$ Formula of copper chloride=CuCl

Hence (a) is the correct answer.

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