Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Electromagnetic Induction
0 votes

A conducting rod AB of length 1 m is moving with uniform speed of $2\;m/s$ in a uniform magnetic field of 4T which is directed perpendicular to the plane of motion of the rod AB. A capacitor of capacity $C= 10\;\mu F$ is connected. The charge on the capacitor is

$(a)\;zero\\ (b)\;is\; varying \\(c)\;is \;40\;\mu F \\(d)\;is 80\; \mu F $

Can you answer this question?

1 Answer

0 votes
where $V$= is induced emf due to the motion of rod in magnetic field $V= Bvl$
$\therefore q= 10 \times 10^{-6} \times 4 \times \times 2 \times 1\;C$
$\qquad= 80 \;\mu C$
Hence d is the correct answer.
answered Mar 21, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App