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$2H_2+O_2\rightarrow 2H_2O$.2g $H_2$ and 1g $O_2$ react to form $H_2O$

$\begin{array}{1 1}(a)\;3.0g& \\ (b)\;1.125g \\(c)\;4.5g \\(d)\;2.50g \end{array}$

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$2H_2(4g)+O_2(32g)\rightarrow 2H_2O(36g)$
$\therefore$ 32g of $O_2$ produces 36g water.
$\therefore$ 1g $O_2$ produces $\large\frac{36}{32}$g of water=1.125g of water
$\therefore$ The option is (b) 1.125g.
answered Mar 21, 2014 by sreemathi.v
 

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