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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Thermodynamics
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Normal body temperature is $\;98.4^{0}F\;.\;$ What is the corresponding reading on the celsius scale ?

$(a)\;37^{0}C\qquad(b)\;29.5^{0}C\qquad(c)\;309.8^{0}C\qquad(d)\;98.4^{0}C$

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1 Answer

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Answer : $\;37^{0}C$
Explanation :
$C=\large\frac{5}{9}\;(F-32)$
$=\large\frac{5}{9}\;[98.4-32] \approx 37^{0}C$
answered Mar 21, 2014 by yamini.v
 

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