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Reaction of $R-CO-NH_2$ with a mixture of $Br_2$ and $KOH$ gives $R-NH_2$ as main product .The intermediate involved in the reaction are \[\] 1. $R-CO-NHBr$ \[\] 11 . $R-N =C=O$ \[\] 111. $R-NH-Br$ \[\] 1v. $H-CO-NBr_2$

$\begin {array} {1 1} (A)\;All & \quad (B)\;1, 11 \\ (C)\;11, 1v & \quad (D)\;only\: 1v \end {array}$

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answered Mar 21, 2014 by thanvigandhi_1

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