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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Thermodynamics

At what temperature is reading on kelvin scale be double that on the celsius scale

$(a)\;546\;K\qquad(b)\;273\;K\qquad(c)\;456\;K\qquad(d)\;732\;K$

1 Answer

Answer : $\;546\;K$
Explanation :
$K-273=C$
$K=C+273=2C$
$C=273^{0}C\;,K=546 K$
answered Mar 21, 2014 by yamini.v
 

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