Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

From 392mg of $H_2SO_4,1.204\times 10^{21}$ molecules are removed.How many moles of $H_2SO_4$ are left?

$\begin{array}{1 1}(a)\;2.0\times 10^{-3}& (b)\;1.2\times 10^{-3} \\(c)\;4.0\times 10^{-3}& (d)\;1.5\times 10^{-3}\end{array}$

Can you answer this question?

1 Answer

0 votes
No of moles of $H_2SO_4=\large\frac{0.392}{98}$$=0.004$
As $N=nN_A$
$\therefore n=\large\frac{N}{N_A}$
$\Rightarrow \large\frac{1.204\times 10^{21}\text{molecules}}{6.023\times 10^{23}\text{molecules}}$
$\Rightarrow 0.002$moles
No of moles of $ H_2SO_4$ left =$0.004-0.002$
$\Rightarrow 0.02$
$\Rightarrow 2.0\times 10^{-3}$
Hence (a) is the correct option.
answered Mar 21, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App