$(a)\;1 \times 10^{-6} \pi V \\ (b)\;2 \times 10^{-3} \pi V \\(c)\;1 \times 10^{-6} V \\(d)\;2 \times 10^{-3} V$

Induced emf $e= \large\frac{d\phi}{dt}$

Where $\phi$ is flux linked with the coil which is BA.

$\qquad= B \pi r^2$

$B= 0.05 \;T$

$\large\frac{dr}{dt} $$=0.5 \times 10^{-3}\;ms^{-1}$

$r= 2 \times 10^{-2}\;m$

$e= \large\frac{d \phi}{dt} =\frac{d}{dt} $$B \pi r^2$

$\qquad=B \pi 2r \large\frac{dr}{dt}$

$\qquad= 0.5 \pi \times 2 \times 2 \times 10^{-2} \times 0.5 \times 10^{-3}$

$\qquad= \pi \times 10^{-3} \times 10^{-2} \times 10^{-1}$

$\qquad= \pi \times 10^{-6}\;V$

Hence a is the correct answer.

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