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Home  >>  CBSE XII  >>  Math  >>  Matrices
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If $\begin{pmatrix} a+4 &3b \\ 8 & -6 \end{pmatrix} = \begin{pmatrix} 2a+2 &b+2 \\ 8 & a-8b \end{pmatrix}$, write the value of $a-2b$.

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If $\begin{pmatrix} a+4 &3b \\ 8 & -6 \end{pmatrix} = \begin{pmatrix} 2a+2 &b+2 \\ 8 & a-8b \end{pmatrix}$:
$\Rightarrow a + 4 = 2a + 2 \rightarrow a = 2$
$\Rightarrow 3b = b+2 \rightarrow b = 1$
$\Rightarrow a - 2b = 2 - 2 \times 1 = 0$
answered Mar 21, 2014 by balaji
 

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