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Number of atoms in 558.5g Fe (at.wt of Fe=$55.85gmol^{-1})$ is

$\begin{array}{1 1}(a)\;6.023\times 10^{22}& (b)\;\text{twice that in 60g carbon} \\(c)\;\text{half that in 8g He}& (d)\;558.5\times 6.023\times 10^{23}\end{array} $

1 Answer

Moles of Fe=$\large\frac{558.5}{55.85}$$=10$moles
Number of atoms in 558.5g of Fe=$10\times 6.023\times 10^{23}$
Mole of c=$\large\frac{60}{12}$$=5$
$\therefore$ Number of atoms in 60g (5mol) of c=$5\times 6.023\times 10^{23}$
$\therefore$ The option is (b) twice that in 60g carbon.
Hence (b) is the correct answer.
answered Mar 21, 2014 by sreemathi.v

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