$\begin{array}{1 1}(a)\;6.023\times 10^{22}& (b)\;\text{twice that in 60g carbon} \\(c)\;\text{half that in 8g He}& (d)\;558.5\times 6.023\times 10^{23}\end{array} $

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Moles of Fe=$\large\frac{558.5}{55.85}$$=10$moles

Number of atoms in 558.5g of Fe=$10\times 6.023\times 10^{23}$

Mole of c=$\large\frac{60}{12}$$=5$

$\therefore$ Number of atoms in 60g (5mol) of c=$5\times 6.023\times 10^{23}$

$\therefore$ The option is (b) twice that in 60g carbon.

Hence (b) is the correct answer.

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